Base | Representation |
---|---|
bin | 100110101111111110000… |
… | …1100001100010001000001 |
3 | 200212010112212201112110010 |
4 | 1031133330030030101001 |
5 | 1144224011024043040 |
6 | 15154331334055133 |
7 | 1056524462060310 |
oct | 115377414142101 |
9 | 20763485645403 |
10 | 5325695534145 |
11 | 1773684319998 |
12 | 7201a47aa4a9 |
13 | 2c8298563b3c |
14 | 145a9d3a6277 |
15 | 93800b91e80 |
hex | 4d7fc30c441 |
5325695534145 has 128 divisors (see below), whose sum is σ = 10539105730560. Its totient is φ = 2242143348480.
The previous prime is 5325695534141. The next prime is 5325695534161. The reversal of 5325695534145 is 5414355965235.
It is not a de Polignac number, because 5325695534145 - 22 = 5325695534141 is a prime.
It is a super-3 number, since 3×53256955341453 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is not an unprimeable number, because it can be changed into a prime (5325695534141) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 17953522 + ... + 18247748.
It is an arithmetic number, because the mean of its divisors is an integer number (82336763520).
Almost surely, 25325695534145 is an apocalyptic number.
It is an amenable number.
5325695534145 is a deficient number, since it is larger than the sum of its proper divisors (5213410196415).
5325695534145 is a wasteful number, since it uses less digits than its factorization.
5325695534145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294515.
The product of its digits is 48600000, while the sum is 57.
The spelling of 5325695534145 in words is "five trillion, three hundred twenty-five billion, six hundred ninety-five million, five hundred thirty-four thousand, one hundred forty-five".
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