Base | Representation |
---|---|
bin | 100110110000001000000… |
… | …1111101101010000010011 |
3 | 200212011102022211202212011 |
4 | 1031200100033231100103 |
5 | 1144230203143000034 |
6 | 15154424553443351 |
7 | 1056536016015343 |
oct | 115402017552023 |
9 | 20764368752764 |
10 | 5326032000019 |
11 | 177383723a765 |
12 | 720279410557 |
13 | 2c832018b983 |
14 | 145ad1d4cd23 |
15 | 938204a5864 |
hex | 4d8103ed413 |
5326032000019 has 2 divisors, whose sum is σ = 5326032000020. Its totient is φ = 5326032000018.
The previous prime is 5326031999993. The next prime is 5326032000041. The reversal of 5326032000019 is 9100002306235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5326032000019 - 215 = 5326031967251 is a prime.
It is a super-2 number, since 2×53260320000192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5326032000049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2663016000009 + 2663016000010.
It is an arithmetic number, because the mean of its divisors is an integer number (2663016000010).
Almost surely, 25326032000019 is an apocalyptic number.
5326032000019 is a deficient number, since it is larger than the sum of its proper divisors (1).
5326032000019 is an equidigital number, since it uses as much as digits as its factorization.
5326032000019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 5326032000019 in words is "five trillion, three hundred twenty-six billion, thirty-two million, nineteen", and thus it is an aban number.
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