Base | Representation |
---|---|
bin | 100110110001010010110… |
… | …0111110000101001001001 |
3 | 200212101212222112101012020 |
4 | 1031202211213300221021 |
5 | 1144300321224014122 |
6 | 15155521400235053 |
7 | 1056655066424115 |
oct | 115424547605111 |
9 | 20771788471166 |
10 | 5328538110537 |
11 | 1774902937684 |
12 | 72085876ba89 |
13 | 2c862c44a4c5 |
14 | 145c8cb10745 |
15 | 9391a4dbc5c |
hex | 4d8a59f0a49 |
5328538110537 has 4 divisors (see below), whose sum is σ = 7104717480720. Its totient is φ = 3552358740356.
The previous prime is 5328538110521. The next prime is 5328538110569. The reversal of 5328538110537 is 7350118358235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5328538110537 - 24 = 5328538110521 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5328538110537.
It is not an unprimeable number, because it can be changed into a prime (5328538110037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 888089685087 + ... + 888089685092.
It is an arithmetic number, because the mean of its divisors is an integer number (1776179370180).
Almost surely, 25328538110537 is an apocalyptic number.
It is an amenable number.
5328538110537 is a deficient number, since it is larger than the sum of its proper divisors (1776179370183).
5328538110537 is a wasteful number, since it uses less digits than its factorization.
5328538110537 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1776179370182.
The product of its (nonzero) digits is 3024000, while the sum is 51.
The spelling of 5328538110537 in words is "five trillion, three hundred twenty-eight billion, five hundred thirty-eight million, one hundred ten thousand, five hundred thirty-seven".
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