Base | Representation |
---|---|
bin | 11000001111011001000101… |
… | …01000010111111110001011 |
3 | 20222201221121101021012010022 |
4 | 30013230202220113332023 |
5 | 23441324000022314242 |
6 | 305212101050011055 |
7 | 14141122001025542 |
oct | 1407544250277613 |
9 | 228657541235108 |
10 | 53305420119947 |
11 | 15a91779a96436 |
12 | 5b8ab45416a8b |
13 | 23988aac77838 |
14 | d23dd3425159 |
15 | 6268e28040d2 |
hex | 307b22a17f8b |
53305420119947 has 2 divisors, whose sum is σ = 53305420119948. Its totient is φ = 53305420119946.
The previous prime is 53305420119827. The next prime is 53305420120003. The reversal of 53305420119947 is 74991102450335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53305420119947 - 28 = 53305420119691 is a prime.
It is not a weakly prime, because it can be changed into another prime (53305420119647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26652710059973 + 26652710059974.
It is an arithmetic number, because the mean of its divisors is an integer number (26652710059974).
Almost surely, 253305420119947 is an apocalyptic number.
53305420119947 is a deficient number, since it is larger than the sum of its proper divisors (1).
53305420119947 is an equidigital number, since it uses as much as digits as its factorization.
53305420119947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 53.
The spelling of 53305420119947 in words is "fifty-three trillion, three hundred five billion, four hundred twenty million, one hundred nineteen thousand, nine hundred forty-seven".
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