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5331126471673 is a prime number
BaseRepresentation
bin100110110010011111111…
…1001100100101111111001
3200212122120100222202011111
41031210333321210233321
51144321121334043143
615201030302000321
71060106166221362
oct115447771445771
920778510882144
105331126471673
111775a10a02712
1272125b5760a1
132c8952776942
141460567a2b69
1593a1c86d99d
hex4d93fe64bf9

5331126471673 has 2 divisors, whose sum is σ = 5331126471674. Its totient is φ = 5331126471672.

The previous prime is 5331126471637. The next prime is 5331126471731. The reversal of 5331126471673 is 3761746211335.

Together with previous prime (5331126471637) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5047535075584 + 283591396089 = 2246672^2 + 532533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5331126471673 is a prime.

It is a super-2 number, since 2×53311264716732 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5331126411673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665563235836 + 2665563235837.

It is an arithmetic number, because the mean of its divisors is an integer number (2665563235837).

Almost surely, 25331126471673 is an apocalyptic number.

It is an amenable number.

5331126471673 is a deficient number, since it is larger than the sum of its proper divisors (1).

5331126471673 is an equidigital number, since it uses as much as digits as its factorization.

5331126471673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1905120, while the sum is 49.

The spelling of 5331126471673 in words is "five trillion, three hundred thirty-one billion, one hundred twenty-six million, four hundred seventy-one thousand, six hundred seventy-three".