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53313523433 = 79674854727
BaseRepresentation
bin110001101001101110…
…111100111011101001
312002121111210121020222
4301221232330323221
51333141230222213
640254125455425
73565105320632
oct615156747351
9162544717228
1053313523433
1120679104275
12a3ba711575
1350483a8591
14281a82a889
1515c0719808
hexc69bbcee9

53313523433 has 4 divisors (see below), whose sum is σ = 53988378240. Its totient is φ = 52638668628.

The previous prime is 53313523429. The next prime is 53313523493. The reversal of 53313523433 is 33432531335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53313523433 - 22 = 53313523429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53313523393 and 53313523402.

It is not an unprimeable number, because it can be changed into a prime (53313523493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337427285 + ... + 337427442.

It is an arithmetic number, because the mean of its divisors is an integer number (13497094560).

Almost surely, 253313523433 is an apocalyptic number.

It is an amenable number.

53313523433 is a deficient number, since it is larger than the sum of its proper divisors (674854807).

53313523433 is an equidigital number, since it uses as much as digits as its factorization.

53313523433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 674854806.

The product of its digits is 145800, while the sum is 35.

The spelling of 53313523433 in words is "fifty-three billion, three hundred thirteen million, five hundred twenty-three thousand, four hundred thirty-three".

Divisors: 1 79 674854727 53313523433