Search a number
-
+
533239504649 is a prime number
BaseRepresentation
bin1111100001001111000…
…11010001111100001001
31212222101101012111120022
413300213203101330021
532214033303122044
61044544501110225
753345113001225
oct7604743217411
91788341174508
10533239504649
111961668872a5
12874189b8375
133b390703917
141bb479bb785
15dd0dd603ee
hex7c278d1f09

533239504649 has 2 divisors, whose sum is σ = 533239504650. Its totient is φ = 533239504648.

The previous prime is 533239504519. The next prime is 533239504669. The reversal of 533239504649 is 946405932335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 428444866249 + 104794638400 = 654557^2 + 323720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-533239504649 is a prime.

It is a super-3 number, since 3×5332395046493 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 533239504649.

It is not a weakly prime, because it can be changed into another prime (533239504669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266619752324 + 266619752325.

It is an arithmetic number, because the mean of its divisors is an integer number (266619752325).

Almost surely, 2533239504649 is an apocalyptic number.

It is an amenable number.

533239504649 is a deficient number, since it is larger than the sum of its proper divisors (1).

533239504649 is an equidigital number, since it uses as much as digits as its factorization.

533239504649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10497600, while the sum is 53.

The spelling of 533239504649 in words is "five hundred thirty-three billion, two hundred thirty-nine million, five hundred four thousand, six hundred forty-nine".