Base | Representation |
---|---|
bin | 1111100001011001001… |
… | …11001011001000001001 |
3 | 1212222121021222012201211 |
4 | 13300230213023020021 |
5 | 32214222022131101 |
6 | 1045001133013121 |
7 | 53350163461615 |
oct | 7605447131011 |
9 | 1788537865654 |
10 | 533324411401 |
11 | 1961aa7a9a71 |
12 | 874413241a1 |
13 | 3b3a51914c2 |
14 | 1bb54da0345 |
15 | dd16532c51 |
hex | 7c2c9cb209 |
533324411401 has 16 divisors (see below), whose sum is σ = 574574054400. Its totient is φ = 493586184960.
The previous prime is 533324411381. The next prime is 533324411407. The reversal of 533324411401 is 104114423335.
It is a cyclic number.
It is not a de Polignac number, because 533324411401 - 221 = 533322314249 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (533324411407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3816501 + ... + 3953773.
It is an arithmetic number, because the mean of its divisors is an integer number (35910878400).
Almost surely, 2533324411401 is an apocalyptic number.
It is an amenable number.
533324411401 is a deficient number, since it is larger than the sum of its proper divisors (41249642999).
533324411401 is a wasteful number, since it uses less digits than its factorization.
533324411401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142776.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 533324411401 its reverse (104114423335), we get a palindrome (637438834736).
The spelling of 533324411401 in words is "five hundred thirty-three billion, three hundred twenty-four million, four hundred eleven thousand, four hundred one".
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