Base | Representation |
---|---|
bin | 1111100001011001010… |
… | …10111111111011101001 |
3 | 1212222121100212011012121 |
4 | 13300230222333323221 |
5 | 32214222301222441 |
6 | 1045001210311241 |
7 | 53350205136163 |
oct | 7605452777351 |
9 | 1788540764177 |
10 | 533325414121 |
11 | 196200324365 |
12 | 87441728521 |
13 | 3b3a5452a26 |
14 | 1bb55181933 |
15 | dd1667edd1 |
hex | 7c2cabfee9 |
533325414121 has 4 divisors (see below), whose sum is σ = 540837039744. Its totient is φ = 525813788500.
The previous prime is 533325414119. The next prime is 533325414151. The reversal of 533325414121 is 121414523335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 533325414121 - 21 = 533325414119 is a prime.
It is a super-2 number, since 2×5333254141212 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (533325414151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3755812705 + ... + 3755812846.
It is an arithmetic number, because the mean of its divisors is an integer number (135209259936).
Almost surely, 2533325414121 is an apocalyptic number.
It is an amenable number.
533325414121 is a deficient number, since it is larger than the sum of its proper divisors (7511625623).
533325414121 is an equidigital number, since it uses as much as digits as its factorization.
533325414121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7511625622.
The product of its digits is 43200, while the sum is 34.
Adding to 533325414121 its reverse (121414523335), we get a palindrome (654739937456).
The spelling of 533325414121 in words is "five hundred thirty-three billion, three hundred twenty-five million, four hundred fourteen thousand, one hundred twenty-one".
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