Base | Representation |
---|---|
bin | 100110110011100011001… |
… | …0001111010110110010001 |
3 | 200212212101111021200102121 |
4 | 1031213012101322312101 |
5 | 1144340231014004333 |
6 | 15202042120214241 |
7 | 1060216103340112 |
oct | 115470621726621 |
9 | 20785344250377 |
10 | 5333381000593 |
11 | 1776968596658 |
12 | 72178a60a381 |
13 | 2c8c2188ac19 |
14 | 1461cbd96209 |
15 | 93b0075c32d |
hex | 4d9c647ad91 |
5333381000593 has 2 divisors, whose sum is σ = 5333381000594. Its totient is φ = 5333381000592.
The previous prime is 5333381000579. The next prime is 5333381000621. The reversal of 5333381000593 is 3950001833335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4200110039889 + 1133270960704 = 2049417^2 + 1064552^2 .
It is a cyclic number.
It is not a de Polignac number, because 5333381000593 - 217 = 5333380869521 is a prime.
It is not a weakly prime, because it can be changed into another prime (5333381000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2666690500296 + 2666690500297.
It is an arithmetic number, because the mean of its divisors is an integer number (2666690500297).
Almost surely, 25333381000593 is an apocalyptic number.
It is an amenable number.
5333381000593 is a deficient number, since it is larger than the sum of its proper divisors (1).
5333381000593 is an equidigital number, since it uses as much as digits as its factorization.
5333381000593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 43.
The spelling of 5333381000593 in words is "five trillion, three hundred thirty-three billion, three hundred eighty-one million, five hundred ninety-three", and thus it is an aban number.
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