Base | Representation |
---|---|
bin | 100110110011100111101… |
… | …0101110110011000001011 |
3 | 200212212210002100100210221 |
4 | 1031213033111312120023 |
5 | 1144341033423311203 |
6 | 15202105150450511 |
7 | 1060222630463233 |
oct | 115471725663013 |
9 | 20785702310727 |
10 | 5333533025803 |
11 | 1776a36391424 |
12 | 721811503a37 |
13 | 2c8c47218878 |
14 | 14620424acc3 |
15 | 93b0dc8babd |
hex | 4d9cf57660b |
5333533025803 has 2 divisors, whose sum is σ = 5333533025804. Its totient is φ = 5333533025802.
The previous prime is 5333533025771. The next prime is 5333533025813. The reversal of 5333533025803 is 3085203353335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5333533025803 - 25 = 5333533025771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5333533025803.
It is not a weakly prime, because it can be changed into another prime (5333533025813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2666766512901 + 2666766512902.
It is an arithmetic number, because the mean of its divisors is an integer number (2666766512902).
Almost surely, 25333533025803 is an apocalyptic number.
5333533025803 is a deficient number, since it is larger than the sum of its proper divisors (1).
5333533025803 is an equidigital number, since it uses as much as digits as its factorization.
5333533025803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458000, while the sum is 43.
The spelling of 5333533025803 in words is "five trillion, three hundred thirty-three billion, five hundred thirty-three million, twenty-five thousand, eight hundred three".
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