Base | Representation |
---|---|
bin | 1111100001100010011… |
… | …00101001010010101011 |
3 | 1212222210122201202020202 |
4 | 13300301030221102223 |
5 | 32214401220440042 |
6 | 1045012521542415 |
7 | 53352116415461 |
oct | 7606114512253 |
9 | 1788718652222 |
10 | 533401343147 |
11 | 19623a174a22 |
12 | 87463044a0b |
13 | 3b3b80b914a |
14 | 1bb612a8831 |
15 | dd1d17c632 |
hex | 7c313294ab |
533401343147 has 2 divisors, whose sum is σ = 533401343148. Its totient is φ = 533401343146.
The previous prime is 533401343077. The next prime is 533401343177. The reversal of 533401343147 is 741343104335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 533401343147 - 238 = 258523436203 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 533401343147.
It is not a weakly prime, because it can be changed into another prime (533401343177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266700671573 + 266700671574.
It is an arithmetic number, because the mean of its divisors is an integer number (266700671574).
Almost surely, 2533401343147 is an apocalyptic number.
533401343147 is a deficient number, since it is larger than the sum of its proper divisors (1).
533401343147 is an equidigital number, since it uses as much as digits as its factorization.
533401343147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 38.
The spelling of 533401343147 in words is "five hundred thirty-three billion, four hundred one million, three hundred forty-three thousand, one hundred forty-seven".
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