Base | Representation |
---|---|
bin | 100110110011110110101… |
… | …0001001111001001001001 |
3 | 200212221002002011001101211 |
4 | 1031213231101033021021 |
5 | 1144343100443224001 |
6 | 15202231044413121 |
7 | 1060241235354511 |
oct | 115475521171111 |
9 | 20787062131354 |
10 | 5334035133001 |
11 | 1777173857a53 |
12 | 7219316a71a1 |
13 | 2c8cc725ab13 |
14 | 146250bd0841 |
15 | 93b3cdbe351 |
hex | 4d9ed44f249 |
5334035133001 has 2 divisors, whose sum is σ = 5334035133002. Its totient is φ = 5334035133000.
The previous prime is 5334035132969. The next prime is 5334035133019. The reversal of 5334035133001 is 1003315304335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5328599757376 + 5435375625 = 2308376^2 + 73725^2 .
It is a cyclic number.
It is not a de Polignac number, because 5334035133001 - 25 = 5334035132969 is a prime.
It is not a weakly prime, because it can be changed into another prime (5334035133701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667017566500 + 2667017566501.
It is an arithmetic number, because the mean of its divisors is an integer number (2667017566501).
Almost surely, 25334035133001 is an apocalyptic number.
It is an amenable number.
5334035133001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334035133001 is an equidigital number, since it uses as much as digits as its factorization.
5334035133001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 31.
The spelling of 5334035133001 in words is "five trillion, three hundred thirty-four billion, thirty-five million, one hundred thirty-three thousand, one".
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