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5334413505521 = 7687693952583
BaseRepresentation
bin100110110100000001111…
…0100100111001111110001
3200212222001110010100220212
41031220003310213033301
51144344334324134041
615202332402313505
71060253511441422
oct115500364471761
920788043110825
105334413505521
1117773483a0911
12721a18358895
132c9057769299
14146289165649
1593b6120e8eb
hex4da03d273f1

5334413505521 has 4 divisors (see below), whose sum is σ = 5335107465792. Its totient is φ = 5333719545252.

The previous prime is 5334413505479. The next prime is 5334413505539. The reversal of 5334413505521 is 1255053144335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5334413505521 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5334413502521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 346968605 + ... + 346983978.

It is an arithmetic number, because the mean of its divisors is an integer number (1333776866448).

Almost surely, 25334413505521 is an apocalyptic number.

It is an amenable number.

5334413505521 is a deficient number, since it is larger than the sum of its proper divisors (693960271).

5334413505521 is an equidigital number, since it uses as much as digits as its factorization.

5334413505521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 693960270.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 5334413505521 its reverse (1255053144335), we get a palindrome (6589466649856).

The spelling of 5334413505521 in words is "five trillion, three hundred thirty-four billion, four hundred thirteen million, five hundred five thousand, five hundred twenty-one".

Divisors: 1 7687 693952583 5334413505521