Base | Representation |
---|---|
bin | 100110110100000010110… |
… | …0101100011100000110011 |
3 | 200212222010111211120001121 |
4 | 1031220011211203200303 |
5 | 1144344414414044444 |
6 | 15202335341043111 |
7 | 1060254321212224 |
oct | 115500545434063 |
9 | 20788114746047 |
10 | 5334443112499 |
11 | 1777363082a96 |
12 | 721a26256497 |
13 | 2c90609343c7 |
14 | 14628d07124b |
15 | 93b63b0c084 |
hex | 4da05963833 |
5334443112499 has 4 divisors (see below), whose sum is σ = 5334452926936. Its totient is φ = 5334433298064.
The previous prime is 5334443112473. The next prime is 5334443112533. The reversal of 5334443112499 is 9942113444335.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5334443112499 - 213 = 5334443104307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5334443112199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4040949 + ... + 5195974.
It is an arithmetic number, because the mean of its divisors is an integer number (1333613231734).
Almost surely, 25334443112499 is an apocalyptic number.
5334443112499 is a deficient number, since it is larger than the sum of its proper divisors (9814437).
5334443112499 is an equidigital number, since it uses as much as digits as its factorization.
5334443112499 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9814436.
The product of its digits is 5598720, while the sum is 52.
The spelling of 5334443112499 in words is "five trillion, three hundred thirty-four billion, four hundred forty-three million, one hundred twelve thousand, four hundred ninety-nine".
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