Base | Representation |
---|---|
bin | 100110110100000101101… |
… | …0111010011101110100001 |
3 | 200212222101021020001010120 |
4 | 1031220023113103232201 |
5 | 1144400114222303441 |
6 | 15202353122350453 |
7 | 1060256606123034 |
oct | 115501327235641 |
9 | 20788337201116 |
10 | 5334540041121 |
11 | 1777402866995 |
12 | 721a527bb429 |
13 | 2c9077a40c15 |
14 | 14629bca301b |
15 | 93b6c3a6966 |
hex | 4da0b5d3ba1 |
5334540041121 has 16 divisors (see below), whose sum is σ = 7491332957184. Its totient is φ = 3369943751504.
The previous prime is 5334540041113. The next prime is 5334540041147. The reversal of 5334540041121 is 1211400454335.
It is a cyclic number.
It is not a de Polignac number, because 5334540041121 - 23 = 5334540041113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5334540041111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 361264461 + ... + 361279226.
It is an arithmetic number, because the mean of its divisors is an integer number (468208309824).
Almost surely, 25334540041121 is an apocalyptic number.
It is an amenable number.
5334540041121 is a deficient number, since it is larger than the sum of its proper divisors (2156792916063).
5334540041121 is a wasteful number, since it uses less digits than its factorization.
5334540041121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 722543820.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 5334540041121 its reverse (1211400454335), we get a palindrome (6545940495456).
The spelling of 5334540041121 in words is "five trillion, three hundred thirty-four billion, five hundred forty million, forty-one thousand, one hundred twenty-one".
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