Base | Representation |
---|---|
bin | 100110110100100000101… |
… | …0001101111110100110011 |
3 | 200220001201022020000011221 |
4 | 1031221001101233310303 |
5 | 1144403442301144021 |
6 | 15203022553245511 |
7 | 1060321201262656 |
oct | 115510121576463 |
9 | 20801638200157 |
10 | 5335444553011 |
11 | 17778273a0081 |
12 | 722065703897 |
13 | 2c9190257161 |
14 | 14634607589d |
15 | 93bc19c5241 |
hex | 4da4146fd33 |
5335444553011 has 2 divisors, whose sum is σ = 5335444553012. Its totient is φ = 5335444553010.
The previous prime is 5335444552961. The next prime is 5335444553029. The reversal of 5335444553011 is 1103554445335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5335444553011 - 225 = 5335410998579 is a prime.
It is a super-2 number, since 2×53354445530112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5335444553041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667722276505 + 2667722276506.
It is an arithmetic number, because the mean of its divisors is an integer number (2667722276506).
Almost surely, 25335444553011 is an apocalyptic number.
5335444553011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5335444553011 is an equidigital number, since it uses as much as digits as its factorization.
5335444553011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 5335444553011 its reverse (1103554445335), we get a palindrome (6438998998346).
The spelling of 5335444553011 in words is "five trillion, three hundred thirty-five billion, four hundred forty-four million, five hundred fifty-three thousand, eleven".
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