Base | Representation |
---|---|
bin | 100110110100100010110… |
… | …0101000110001111000011 |
3 | 200220001220100001012102211 |
4 | 1031221011211012033003 |
5 | 1144404114241000103 |
6 | 15203034052322551 |
7 | 1060323035643232 |
oct | 115510545061703 |
9 | 20801810035384 |
10 | 5335516734403 |
11 | 1777864111019 |
12 | 722085913457 |
13 | 2c91a21aa83b |
14 | 1463518a4b19 |
15 | 93bc7ed236d |
hex | 4da459463c3 |
5335516734403 has 8 divisors (see below), whose sum is σ = 5459629934000. Its totient is φ = 5211404962848.
The previous prime is 5335516734323. The next prime is 5335516734481. The reversal of 5335516734403 is 3044376155335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5335516734403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5335516734703) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12650773 + ... + 13065721.
It is an arithmetic number, because the mean of its divisors is an integer number (682453741750).
Almost surely, 25335516734403 is an apocalyptic number.
5335516734403 is a deficient number, since it is larger than the sum of its proper divisors (124113199597).
5335516734403 is a wasteful number, since it uses less digits than its factorization.
5335516734403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 714021.
The product of its (nonzero) digits is 6804000, while the sum is 49.
The spelling of 5335516734403 in words is "five trillion, three hundred thirty-five billion, five hundred sixteen million, seven hundred thirty-four thousand, four hundred three".
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