Base | Representation |
---|---|
bin | 11000010001110001101101… |
… | …11011110110010010000001 |
3 | 21000000210010021021220201001 |
4 | 30020320312323312102001 |
5 | 23444144310434212102 |
6 | 305313452244212001 |
7 | 14150052451205323 |
oct | 1410706673662201 |
9 | 230023107256631 |
10 | 53387365147777 |
11 | 160134aa902731 |
12 | 5ba29b469a001 |
13 | 23a353a04a39b |
14 | d27d68629613 |
15 | 628adb927487 |
hex | 308e36ef6481 |
53387365147777 has 4 divisors (see below), whose sum is σ = 53655643364800. Its totient is φ = 53119086930756.
The previous prime is 53387365147757. The next prime is 53387365147799. The reversal of 53387365147777 is 77774156378335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53387365147777 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53387365147757) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134139108213 + ... + 134139108610.
It is an arithmetic number, because the mean of its divisors is an integer number (13413910841200).
Almost surely, 253387365147777 is an apocalyptic number.
It is an amenable number.
53387365147777 is a deficient number, since it is larger than the sum of its proper divisors (268278217023).
53387365147777 is a wasteful number, since it uses less digits than its factorization.
53387365147777 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268278217022.
The product of its digits is 2178187200, while the sum is 73.
The spelling of 53387365147777 in words is "fifty-three trillion, three hundred eighty-seven billion, three hundred sixty-five million, one hundred forty-seven thousand, seven hundred seventy-seven".
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