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53400121 is a prime number
BaseRepresentation
bin1100101110110…
…1001000111001
310201111000012021
43023231020321
5102132300441
65144314441
71215615325
oct313551071
9121430167
1053400121
1128163335
1215a72a21
13b0a8c08
147140985
154a4c3d1
hex32ed239

53400121 has 2 divisors, whose sum is σ = 53400122. Its totient is φ = 53400120.

The previous prime is 53400103. The next prime is 53400143. The reversal of 53400121 is 12100435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51265600 + 2134521 = 7160^2 + 1461^2 .

It is a cyclic number.

It is not a de Polignac number, because 53400121 - 211 = 53398073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53400095 and 53400104.

It is not a weakly prime, because it can be changed into another prime (53400101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700060 + 26700061.

It is an arithmetic number, because the mean of its divisors is an integer number (26700061).

Almost surely, 253400121 is an apocalyptic number.

It is an amenable number.

53400121 is a deficient number, since it is larger than the sum of its proper divisors (1).

53400121 is an equidigital number, since it uses as much as digits as its factorization.

53400121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 53400121 is about 7307.5386417042. The cubic root of 53400121 is about 376.5714700124.

Adding to 53400121 its reverse (12100435), we get a palindrome (65500556).

The spelling of 53400121 in words is "fifty-three million, four hundred thousand, one hundred twenty-one".