Base | Representation |
---|---|
bin | 100110110110101001010… |
… | …1101111001001101011010 |
3 | 200220111120000112010021202 |
4 | 1031231102231321031122 |
5 | 1144442341210031300 |
6 | 15205102112434202 |
7 | 1060542655006631 |
oct | 115552255711532 |
9 | 20814500463252 |
10 | 5340032111450 |
11 | 1779770a04693 |
12 | 722b25b48962 |
13 | 2c974180948a |
14 | 14665d454518 |
15 | 93d8e60bad5 |
hex | 4db52b7935a |
5340032111450 has 12 divisors (see below), whose sum is σ = 9932459727390. Its totient is φ = 2136012844560.
The previous prime is 5340032111417. The next prime is 5340032111503. The reversal of 5340032111450 is 541112300435.
It can be written as a sum of positive squares in 3 ways, for example, as 1987679842201 + 3352352269249 = 1409851^2 + 1830943^2 .
It is a super-2 number, since 2×53400321114502 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 53400321065 + ... + 53400321164.
Almost surely, 25340032111450 is an apocalyptic number.
5340032111450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5340032111450 is a deficient number, since it is larger than the sum of its proper divisors (4592427615940).
5340032111450 is a wasteful number, since it uses less digits than its factorization.
5340032111450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106800642241 (or 106800642236 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 5340032111450 its reverse (541112300435), we get a palindrome (5881144411885).
The spelling of 5340032111450 in words is "five trillion, three hundred forty billion, thirty-two million, one hundred eleven thousand, four hundred fifty".
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