Base | Representation |
---|---|
bin | 11000010010001101110001… |
… | …11001000010100001011011 |
3 | 21000002020000012010120000111 |
4 | 30021012320321002201123 |
5 | 23444421134132221301 |
6 | 305324423211545151 |
7 | 14151125002264036 |
oct | 1411067071024133 |
9 | 230066005116014 |
10 | 53402430351451 |
11 | 1601993080a185 |
12 | 5ba58b9a5b1b7 |
13 | 23a4a9b245a9c |
14 | d2899738401d |
15 | 6291be31b551 |
hex | 3091b8e4285b |
53402430351451 has 2 divisors, whose sum is σ = 53402430351452. Its totient is φ = 53402430351450.
The previous prime is 53402430351377. The next prime is 53402430351511. The reversal of 53402430351451 is 15415303420435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53402430351451 - 29 = 53402430350939 is a prime.
It is not a weakly prime, because it can be changed into another prime (53402430361451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26701215175725 + 26701215175726.
It is an arithmetic number, because the mean of its divisors is an integer number (26701215175726).
Almost surely, 253402430351451 is an apocalyptic number.
53402430351451 is a deficient number, since it is larger than the sum of its proper divisors (1).
53402430351451 is an equidigital number, since it uses as much as digits as its factorization.
53402430351451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 53402430351451 its reverse (15415303420435), we get a palindrome (68817733771886).
The spelling of 53402430351451 in words is "fifty-three trillion, four hundred two billion, four hundred thirty million, three hundred fifty-one thousand, four hundred fifty-one".
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