Base | Representation |
---|---|
bin | 100110110110110100101… |
… | …0011101000100011010001 |
3 | 200220112112102122220120011 |
4 | 1031231221103220203101 |
5 | 1144444130220302231 |
6 | 15205203451514521 |
7 | 1060555236253561 |
oct | 115555123504321 |
9 | 20815472586504 |
10 | 5340411103441 |
11 | 1779945930a07 |
12 | 723010a58a41 |
13 | 2c97a21a38ab |
14 | 14669790ada1 |
15 | 93db2a209b1 |
hex | 4db694e88d1 |
5340411103441 has 2 divisors, whose sum is σ = 5340411103442. Its totient is φ = 5340411103440.
The previous prime is 5340411103373. The next prime is 5340411103471. The reversal of 5340411103441 is 1443011140435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5131923890625 + 208487212816 = 2265375^2 + 456604^2 .
It is a cyclic number.
It is not a de Polignac number, because 5340411103441 - 229 = 5339874232529 is a prime.
It is not a weakly prime, because it can be changed into another prime (5340411103471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670205551720 + 2670205551721.
It is an arithmetic number, because the mean of its divisors is an integer number (2670205551721).
Almost surely, 25340411103441 is an apocalyptic number.
It is an amenable number.
5340411103441 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340411103441 is an equidigital number, since it uses as much as digits as its factorization.
5340411103441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 5340411103441 its reverse (1443011140435), we get a palindrome (6783422243876).
The spelling of 5340411103441 in words is "five trillion, three hundred forty billion, four hundred eleven million, one hundred three thousand, four hundred forty-one".
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