Base | Representation |
---|---|
bin | 111100101101101111110101… |
… | …0010101111011110100101011 |
3 | 2121000220222021022002200010100 |
4 | 1321123133222111323310223 |
5 | 1024444411121311331011 |
6 | 5131500330110520443 |
7 | 220330026303121614 |
oct | 17133375225736453 |
9 | 2530828238080110 |
10 | 534053050105131 |
11 | 145190699060687 |
12 | 4ba93085b06123 |
13 | 19bcbca9546acb |
14 | 95c443c5a2c0b |
15 | 41b1e2abb6d56 |
hex | 1e5b7ea57bd2b |
534053050105131 has 6 divisors (see below), whose sum is σ = 771409961262980. Its totient is φ = 356035366736748.
The previous prime is 534053050105121. The next prime is 534053050105139. The reversal of 534053050105131 is 131501050350435.
534053050105131 is a `hidden beast` number, since 5 + 3 + 4 + 0 + 530 + 5 + 0 + 105 + 13 + 1 = 666.
It is not a de Polignac number, because 534053050105131 - 29 = 534053050104619 is a prime.
It is a super-2 number, since 2×5340530501051312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534053050105139) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 29669613894721 + ... + 29669613894738.
Almost surely, 2534053050105131 is an apocalyptic number.
534053050105131 is a deficient number, since it is larger than the sum of its proper divisors (237356911157849).
534053050105131 is a wasteful number, since it uses less digits than its factorization.
534053050105131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59339227789465 (or 59339227789462 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 36.
The spelling of 534053050105131 in words is "five hundred thirty-four trillion, fifty-three billion, fifty million, one hundred five thousand, one hundred thirty-one".
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