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534104445242 = 2267052222621
BaseRepresentation
bin1111100010110110001…
…10110001000100111010
31220001121122202001000002
413301123012301010322
532222321214221432
61045210355513002
753405414610014
oct7613306610472
91801548661002
10534104445242
11196570042a35
128761a5b8762
133b49a9734a4
141bbca80d1b4
15dd5ec63e62
hex7c5b1b113a

534104445242 has 4 divisors (see below), whose sum is σ = 801156667866. Its totient is φ = 267052222620.

The previous prime is 534104445233. The next prime is 534104445247. The reversal of 534104445242 is 242544401435.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 533953179841 + 151265401 = 730721^2 + 12299^2 .

It is a junction number, because it is equal to n+sod(n) for n = 534104445196 and 534104445205.

It is not an unprimeable number, because it can be changed into a prime (534104445247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133526111309 + ... + 133526111312.

Almost surely, 2534104445242 is an apocalyptic number.

534104445242 is a deficient number, since it is larger than the sum of its proper divisors (267052222624).

534104445242 is a wasteful number, since it uses less digits than its factorization.

534104445242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267052222623.

The product of its (nonzero) digits is 307200, while the sum is 38.

Adding to 534104445242 its reverse (242544401435), we get a palindrome (776648846677).

The spelling of 534104445242 in words is "five hundred thirty-four billion, one hundred four million, four hundred forty-five thousand, two hundred forty-two".

Divisors: 1 2 267052222621 534104445242