Base | Representation |
---|---|
bin | 100110110111001101011… |
… | …1011100011111110100011 |
3 | 200220121200110020212021221 |
4 | 1031232122323203332203 |
5 | 1200002331333412201 |
6 | 15205422232155511 |
7 | 1060614665651044 |
oct | 115563273437643 |
9 | 20817613225257 |
10 | 5341243654051 |
11 | 177a232884568 |
12 | 723203838b97 |
13 | 2c98a58126a6 |
14 | 14673630a8cb |
15 | 93e10b774a1 |
hex | 4db9aee3fa3 |
5341243654051 has 8 divisors (see below), whose sum is σ = 5410194628608. Its totient is φ = 5272719621000.
The previous prime is 5341243654013. The next prime is 5341243654067. The reversal of 5341243654051 is 1504563421435.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5341243654051 - 29 = 5341243653539 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5341243653989 and 5341243654007.
It is not an unprimeable number, because it can be changed into a prime (5341243654001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 106710195 + ... + 106760236.
It is an arithmetic number, because the mean of its divisors is an integer number (676274328576).
Almost surely, 25341243654051 is an apocalyptic number.
5341243654051 is a deficient number, since it is larger than the sum of its proper divisors (68950974557).
5341243654051 is a wasteful number, since it uses less digits than its factorization.
5341243654051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213470753.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 5341243654051 in words is "five trillion, three hundred forty-one billion, two hundred forty-three million, six hundred fifty-four thousand, fifty-one".
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