Search a number
-
+
53431355313433 is a prime number
BaseRepresentation
bin11000010011000011101001…
…11101000000110100011001
321000011222200000112212110201
430021201310331000310121
524000404403430012213
6305350005322142201
714153200536353206
oct1411416475006431
9230158600485421
1053431355313433
1116030124138239
125bab430951961
1323a772a989cc6
14d2a13cb0acad
15629d138906dd
hex309874f40d19

53431355313433 has 2 divisors, whose sum is σ = 53431355313434. Its totient is φ = 53431355313432.

The previous prime is 53431355313389. The next prime is 53431355313487. The reversal of 53431355313433 is 33431355313435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53229675281689 + 201680031744 = 7295867^2 + 449088^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53431355313433 is a prime.

It is not a weakly prime, because it can be changed into another prime (53431355316433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26715677656716 + 26715677656717.

It is an arithmetic number, because the mean of its divisors is an integer number (26715677656717).

Almost surely, 253431355313433 is an apocalyptic number.

It is an amenable number.

53431355313433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53431355313433 is an equidigital number, since it uses as much as digits as its factorization.

53431355313433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4374000, while the sum is 46.

The spelling of 53431355313433 in words is "fifty-three trillion, four hundred thirty-one billion, three hundred fifty-five million, three hundred thirteen thousand, four hundred thirty-three".