Base | Representation |
---|---|
bin | 100110111000000111110… |
… | …1010011111111001011001 |
3 | 200220210201221102222212121 |
4 | 1031300033222133321121 |
5 | 1200020334220141121 |
6 | 15210344432541241 |
7 | 1061014346415151 |
oct | 115601752377131 |
9 | 20823657388777 |
10 | 5343202115161 |
11 | 178004832a369 |
12 | 72366b6b1821 |
13 | 2c9b284a4911 |
14 | 146880471761 |
15 | 93ec7a82141 |
hex | 4dc0fa9fe59 |
5343202115161 has 2 divisors, whose sum is σ = 5343202115162. Its totient is φ = 5343202115160.
The previous prime is 5343202115131. The next prime is 5343202115177. The reversal of 5343202115161 is 1615112023435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5310346927561 + 32855187600 = 2304419^2 + 181260^2 .
It is a cyclic number.
It is not a de Polignac number, because 5343202115161 - 223 = 5343193726553 is a prime.
It is not a weakly prime, because it can be changed into another prime (5343202115131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671601057580 + 2671601057581.
It is an arithmetic number, because the mean of its divisors is an integer number (2671601057581).
Almost surely, 25343202115161 is an apocalyptic number.
It is an amenable number.
5343202115161 is a deficient number, since it is larger than the sum of its proper divisors (1).
5343202115161 is an equidigital number, since it uses as much as digits as its factorization.
5343202115161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 5343202115161 its reverse (1615112023435), we get a palindrome (6958314138596).
The spelling of 5343202115161 in words is "five trillion, three hundred forty-three billion, two hundred two million, one hundred fifteen thousand, one hundred sixty-one".
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