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5343234454121 = 26479201791399
BaseRepresentation
bin100110111000001000110…
…0101110111001001101001
3200220210211012021222120212
41031300101211313021221
51200020421010012441
615210351550030505
71061015221324634
oct115602145671151
920823735258525
105343234454121
111780064608083
1272367a4a8435
132c9b320b83b5
1414688488cc1b
1593eca81deeb
hex4dc11977269

5343234454121 has 4 divisors (see below), whose sum is σ = 5343436272000. Its totient is φ = 5343032636244.

The previous prime is 5343234454097. The next prime is 5343234454141. The reversal of 5343234454121 is 1214544323435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5343234454121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5343234454141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100869221 + ... + 100922178.

It is an arithmetic number, because the mean of its divisors is an integer number (1335859068000).

Almost surely, 25343234454121 is an apocalyptic number.

It is an amenable number.

5343234454121 is a deficient number, since it is larger than the sum of its proper divisors (201817879).

5343234454121 is a wasteful number, since it uses less digits than its factorization.

5343234454121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201817878.

The product of its digits is 691200, while the sum is 41.

Adding to 5343234454121 its reverse (1214544323435), we get a palindrome (6557778777556).

The spelling of 5343234454121 in words is "five trillion, three hundred forty-three billion, two hundred thirty-four million, four hundred fifty-four thousand, one hundred twenty-one".

Divisors: 1 26479 201791399 5343234454121