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534334004023044 = 22347403979393271
BaseRepresentation
bin111100101111110010101010…
…0100000000100111100000100
32121001220211110110110110222210
41321133211110200010330010
51030014012020012214134
65132233352552223420
7220356233511042201
oct17137452440047404
92531824413413883
10534334004023044
11145289862237575
124bb1961499ab70
1319c1c6324c1c54
1495d3c91db2ca8
1541b93c12372e9
hex1e5f954804f04

534334004023044 has 24 divisors (see below), whose sum is σ = 1246779738463168. Its totient is φ = 178111278139680.

The previous prime is 534334004023033. The next prime is 534334004023121. The reversal of 534334004023044 is 440320400433435.

It is a junction number, because it is equal to n+sod(n) for n = 534334004022993 and 534334004023011.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52188129 + ... + 61581399.

Almost surely, 2534334004023044 is an apocalyptic number.

It is an amenable number.

534334004023044 is an abundant number, since it is smaller than the sum of its proper divisors (712445734440124).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

534334004023044 is a wasteful number, since it uses less digits than its factorization.

534334004023044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14133675 (or 14133673 counting only the distinct ones).

The product of its (nonzero) digits is 829440, while the sum is 39.

Adding to 534334004023044 its reverse (440320400433435), we get a palindrome (974654404456479).

The spelling of 534334004023044 in words is "five hundred thirty-four trillion, three hundred thirty-four billion, four million, twenty-three thousand, forty-four".

Divisors: 1 2 3 4 6 12 4740397 9393271 9480794 14221191 18786542 18961588 28179813 28442382 37573084 56359626 56884764 112719252 44527833668587 89055667337174 133583501005761 178111334674348 267167002011522 534334004023044