Base | Representation |
---|---|
bin | 111100101111110010101010… |
… | …0100000000100111100000100 |
3 | 2121001220211110110110110222210 |
4 | 1321133211110200010330010 |
5 | 1030014012020012214134 |
6 | 5132233352552223420 |
7 | 220356233511042201 |
oct | 17137452440047404 |
9 | 2531824413413883 |
10 | 534334004023044 |
11 | 145289862237575 |
12 | 4bb1961499ab70 |
13 | 19c1c6324c1c54 |
14 | 95d3c91db2ca8 |
15 | 41b93c12372e9 |
hex | 1e5f954804f04 |
534334004023044 has 24 divisors (see below), whose sum is σ = 1246779738463168. Its totient is φ = 178111278139680.
The previous prime is 534334004023033. The next prime is 534334004023121. The reversal of 534334004023044 is 440320400433435.
It is a junction number, because it is equal to n+sod(n) for n = 534334004022993 and 534334004023011.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52188129 + ... + 61581399.
Almost surely, 2534334004023044 is an apocalyptic number.
It is an amenable number.
534334004023044 is an abundant number, since it is smaller than the sum of its proper divisors (712445734440124).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
534334004023044 is a wasteful number, since it uses less digits than its factorization.
534334004023044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14133675 (or 14133673 counting only the distinct ones).
The product of its (nonzero) digits is 829440, while the sum is 39.
Adding to 534334004023044 its reverse (440320400433435), we get a palindrome (974654404456479).
The spelling of 534334004023044 in words is "five hundred thirty-four trillion, three hundred thirty-four billion, four million, twenty-three thousand, forty-four".
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