Base | Representation |
---|---|
bin | 1111100011010001110… |
… | …11000000100111100001 |
3 | 1220002012210220122101102 |
4 | 13301220323000213201 |
5 | 32223310034303233 |
6 | 1045245400044145 |
7 | 53414231064503 |
oct | 7615073004741 |
9 | 1802183818342 |
10 | 534336244193 |
11 | 196679974a14 |
12 | 87684163655 |
13 | 3b5069b252b |
14 | 1bc0d50bd73 |
15 | dd752a01e8 |
hex | 7c68ec09e1 |
534336244193 has 2 divisors, whose sum is σ = 534336244194. Its totient is φ = 534336244192.
The previous prime is 534336244157. The next prime is 534336244207. The reversal of 534336244193 is 391442633435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 530788016704 + 3548227489 = 728552^2 + 59567^2 .
It is a cyclic number.
It is not a de Polignac number, because 534336244193 - 218 = 534335982049 is a prime.
It is not a weakly prime, because it can be changed into another prime (534336244153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267168122096 + 267168122097.
It is an arithmetic number, because the mean of its divisors is an integer number (267168122097).
Almost surely, 2534336244193 is an apocalyptic number.
It is an amenable number.
534336244193 is a deficient number, since it is larger than the sum of its proper divisors (1).
534336244193 is an equidigital number, since it uses as much as digits as its factorization.
534336244193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 47.
The spelling of 534336244193 in words is "five hundred thirty-four billion, three hundred thirty-six million, two hundred forty-four thousand, one hundred ninety-three".
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