Base | Representation |
---|---|
bin | 110001110000111001… |
… | …001000101010011010 |
3 | 12002220212210211012112 |
4 | 301300321020222122 |
5 | 1333413002232214 |
6 | 40314100112322 |
7 | 3601064250566 |
oct | 616071105232 |
9 | 162825724175 |
10 | 53433633434 |
11 | 2072a990735 |
12 | a4329956a2 |
13 | 506724059c |
14 | 282c7746a6 |
15 | 15cb042a3e |
hex | c70e48a9a |
53433633434 has 16 divisors (see below), whose sum is σ = 82059014400. Its totient is φ = 26095417740.
The previous prime is 53433633427. The next prime is 53433633593. The reversal of 53433633434 is 43433633435.
It is a junction number, because it is equal to n+sod(n) for n = 53433633391 and 53433633400.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9002 + ... + 327029.
It is an arithmetic number, because the mean of its divisors is an integer number (5128688400).
Almost surely, 253433633434 is an apocalyptic number.
53433633434 is a deficient number, since it is larger than the sum of its proper divisors (28625380966).
53433633434 is an frugal number, since it uses more digits than its factorization.
53433633434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 336162 (or 336076 counting only the distinct ones).
The product of its digits is 1399680, while the sum is 41.
Subtracting from 53433633434 its reverse (43433633435), we obtain a palindrome (9999999999).
The spelling of 53433633434 in words is "fifty-three billion, four hundred thirty-three million, six hundred thirty-three thousand, four hundred thirty-four".
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