Base | Representation |
---|---|
bin | 110001110000111001… |
… | …001000101001101111 |
3 | 12002220212210211010221 |
4 | 301300321020221233 |
5 | 1333413002232031 |
6 | 40314100112211 |
7 | 3601064250505 |
oct | 616071105157 |
9 | 162825724127 |
10 | 53433633391 |
11 | 2072a9906a6 |
12 | a432995667 |
13 | 5067240568 |
14 | 282c774675 |
15 | 15cb042a11 |
hex | c70e48a6f |
53433633391 has 8 divisors (see below), whose sum is σ = 56009845584. Its totient is φ = 50918038080.
The previous prime is 53433633359. The next prime is 53433633401. The reversal of 53433633391 is 19333633435.
53433633391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53433633391 - 25 = 53433633359 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53433633301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15152416 + ... + 15155941.
It is an arithmetic number, because the mean of its divisors is an integer number (7001230698).
Almost surely, 253433633391 is an apocalyptic number.
53433633391 is a deficient number, since it is larger than the sum of its proper divisors (2576212193).
53433633391 is a wasteful number, since it uses less digits than its factorization.
53433633391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30308441.
The product of its digits is 787320, while the sum is 43.
The spelling of 53433633391 in words is "fifty-three billion, four hundred thirty-three million, six hundred thirty-three thousand, three hundred ninety-one".
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