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53435113 = 67797539
BaseRepresentation
bin1100101111010…
…1101011101001
310201112210012021
43023311223221
5102134410423
65145144441
71216122334
oct313655351
9121483167
1053435113
1128187656
1215a8b121
13b0bbb14
14714d61b
154a5795d
hex32f5ae9

53435113 has 4 divisors (see below), whose sum is σ = 54232720. Its totient is φ = 52637508.

The previous prime is 53435093. The next prime is 53435147. The reversal of 53435113 is 31153435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53435113 - 221 = 51337961 is a prime.

It is a super-2 number, since 2×534351132 = 5710622602645538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53435153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 398703 + ... + 398836.

It is an arithmetic number, because the mean of its divisors is an integer number (13558180).

Almost surely, 253435113 is an apocalyptic number.

It is an amenable number.

53435113 is a deficient number, since it is larger than the sum of its proper divisors (797607).

53435113 is an equidigital number, since it uses as much as digits as its factorization.

53435113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 797606.

The product of its digits is 2700, while the sum is 25.

The square root of 53435113 is about 7309.9324894283. The cubic root of 53435113 is about 376.6537052301.

Adding to 53435113 its reverse (31153435), we get a palindrome (84588548).

The spelling of 53435113 in words is "fifty-three million, four hundred thirty-five thousand, one hundred thirteen".

Divisors: 1 67 797539 53435113