Base | Representation |
---|---|
bin | 111100101111111111100001… |
… | …1001011001001101000100011 |
3 | 2121002000110202210202121111021 |
4 | 1321133333003023021220203 |
5 | 1030014440104414041003 |
6 | 5132254202202030311 |
7 | 220361232231135265 |
oct | 17137770313115043 |
9 | 2532013683677437 |
10 | 534361630612003 |
11 | 14529a549779777 |
12 | 4bb22a44aa8397 |
13 | 19c22115c4a8cc |
14 | 95d535311db35 |
15 | 41b9e8b7dd2bd |
hex | 1e5ffc32c9a23 |
534361630612003 has 4 divisors (see below), whose sum is σ = 534361681187080. Its totient is φ = 534361580036928.
The previous prime is 534361630611937. The next prime is 534361630612049. The reversal of 534361630612003 is 300216036163435.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 534361630612003 - 233 = 534353040677411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534361630613003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2733825 + ... + 32805442.
It is an arithmetic number, because the mean of its divisors is an integer number (133590420296770).
Almost surely, 2534361630612003 is an apocalyptic number.
534361630612003 is a deficient number, since it is larger than the sum of its proper divisors (50575077).
534361630612003 is a wasteful number, since it uses less digits than its factorization.
534361630612003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50575076.
The product of its (nonzero) digits is 699840, while the sum is 43.
Adding to 534361630612003 its reverse (300216036163435), we get a palindrome (834577666775438).
The spelling of 534361630612003 in words is "five hundred thirty-four trillion, three hundred sixty-one billion, six hundred thirty million, six hundred twelve thousand, three".
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