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53441433 = 3219595297
BaseRepresentation
bin1100101111011…
…1001110011001
310201120002212100
43023313032121
5102140111213
65145234013
71216146633
oct313671631
9121502770
1053441433
1128191381
1215a92909
13b0c1966
147151a53
154a59773
hex32f7399

53441433 has 24 divisors (see below), whose sum is σ = 82648800. Its totient is φ = 33174144.

The previous prime is 53441419. The next prime is 53441441. The reversal of 53441433 is 33414435.

It is not a de Polignac number, because 53441433 - 26 = 53441369 is a prime.

It is a super-2 number, since 2×534414332 = 5711973522186978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53441397 and 53441406.

It is not an unprimeable number, because it can be changed into a prime (53441413) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7441 + ... + 12737.

It is an arithmetic number, because the mean of its divisors is an integer number (3443700).

Almost surely, 253441433 is an apocalyptic number.

It is an amenable number.

53441433 is a deficient number, since it is larger than the sum of its proper divisors (29207367).

53441433 is a wasteful number, since it uses less digits than its factorization.

53441433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5381 (or 5378 counting only the distinct ones).

The product of its digits is 8640, while the sum is 27.

The square root of 53441433 is about 7310.3647651810. The cubic root of 53441433 is about 376.6685541277.

Adding to 53441433 its reverse (33414435), we get a palindrome (86855868).

The spelling of 53441433 in words is "fifty-three million, four hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 3 9 19 57 59 171 177 531 1121 3363 5297 10089 15891 47673 100643 301929 312523 905787 937569 2812707 5937937 17813811 53441433