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53443147 is a prime number
BaseRepresentation
bin1100101111011…
…1101001001011
310201120012012211
43023313221023
5102140140042
65145245551
71216154632
oct313675113
9121505184
1053443147
112819269a
1215a938b7
13b0c2684
147152519
154a5a017
hex32f7a4b

53443147 has 2 divisors, whose sum is σ = 53443148. Its totient is φ = 53443146.

The previous prime is 53443129. The next prime is 53443211. The reversal of 53443147 is 74134435.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53443147 is a prime.

It is a super-2 number, since 2×534431472 = 5712339922527218, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (53443127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26721573 + 26721574.

It is an arithmetic number, because the mean of its divisors is an integer number (26721574).

Almost surely, 253443147 is an apocalyptic number.

53443147 is a deficient number, since it is larger than the sum of its proper divisors (1).

53443147 is an equidigital number, since it uses as much as digits as its factorization.

53443147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20160, while the sum is 31.

The square root of 53443147 is about 7310.4819950534. The cubic root of 53443147 is about 376.6725809846.

It can be divided in two parts, 534 and 43147, that added together give a square (43681 = 2092).

The spelling of 53443147 in words is "fifty-three million, four hundred forty-three thousand, one hundred forty-seven".