Base | Representation |
---|---|
bin | 1001111101001001… |
… | …10011010100100001 |
3 | 111210111012002002122 |
4 | 10332210303110201 |
5 | 41421232131311 |
6 | 2242205354025 |
7 | 246310032233 |
oct | 47644632441 |
9 | 14714162078 |
10 | 5344802081 |
11 | 22a3001a03 |
12 | 1051b68915 |
13 | 672414ba8 |
14 | 389bb8253 |
15 | 2143650db |
hex | 13e933521 |
5344802081 has 2 divisors, whose sum is σ = 5344802082. Its totient is φ = 5344802080.
The previous prime is 5344802053. The next prime is 5344802137. The reversal of 5344802081 is 1802084435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4703902225 + 640899856 = 68585^2 + 25316^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5344802081 is a prime.
It is a super-2 number, since 2×53448020812 = 57133818570123861122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5344802041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672401040 + 2672401041.
It is an arithmetic number, because the mean of its divisors is an integer number (2672401041).
Almost surely, 25344802081 is an apocalyptic number.
It is an amenable number.
5344802081 is a deficient number, since it is larger than the sum of its proper divisors (1).
5344802081 is an equidigital number, since it uses as much as digits as its factorization.
5344802081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30720, while the sum is 35.
The square root of 5344802081 is about 73108.1533141140. The cubic root of 5344802081 is about 1748.4123920961.
The spelling of 5344802081 in words is "five billion, three hundred forty-four million, eight hundred two thousand, eighty-one".
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