Base | Representation |
---|---|
bin | 100110111001011110010… |
… | …1100100110101011100011 |
3 | 200221002020020222012112212 |
4 | 1031302330230212223203 |
5 | 1200042310403004403 |
6 | 15211544454312335 |
7 | 1061146316534354 |
oct | 115627454465343 |
9 | 20832206865485 |
10 | 5346105125603 |
11 | 17812a7a75050 |
12 | 72413b9586ab |
13 | 2ca19ba5a988 |
14 | 146a77c2bd2b |
15 | 940e78684d8 |
hex | 4dcbcb26ae3 |
5346105125603 has 16 divisors (see below), whose sum is σ = 6196282155360. Its totient is φ = 4565681568000.
The previous prime is 5346105125567. The next prime is 5346105125623. The reversal of 5346105125603 is 3065215016435.
It is a cyclic number.
It is not a de Polignac number, because 5346105125603 - 222 = 5346100931299 is a prime.
It is a super-2 number, since 2×53461051256032 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5346105125623) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 226460498 + ... + 226484103.
It is an arithmetic number, because the mean of its divisors is an integer number (387267634710).
Almost surely, 25346105125603 is an apocalyptic number.
5346105125603 is a deficient number, since it is larger than the sum of its proper divisors (850177029757).
5346105125603 is a wasteful number, since it uses less digits than its factorization.
5346105125603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 452944678.
The product of its (nonzero) digits is 324000, while the sum is 41.
The spelling of 5346105125603 in words is "five trillion, three hundred forty-six billion, one hundred five million, one hundred twenty-five thousand, six hundred three".
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