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53474833 is a prime number
BaseRepresentation
bin1100101111111…
…1011000010001
310201121210200101
43023333120101
5102142143313
65150052401
71216346206
oct313773021
9121553611
1053474833
1128204485
1215aaa101
13b103c19
14715dcad
154a645dd
hex32ff611

53474833 has 2 divisors, whose sum is σ = 53474834. Its totient is φ = 53474832.

The previous prime is 53474807. The next prime is 53474851. The reversal of 53474833 is 33847435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46335249 + 7139584 = 6807^2 + 2672^2 .

It is a cyclic number.

It is not a de Polignac number, because 53474833 - 25 = 53474801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53474792 and 53474801.

It is not a weakly prime, because it can be changed into another prime (53474803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26737416 + 26737417.

It is an arithmetic number, because the mean of its divisors is an integer number (26737417).

Almost surely, 253474833 is an apocalyptic number.

It is an amenable number.

53474833 is a deficient number, since it is larger than the sum of its proper divisors (1).

53474833 is an equidigital number, since it uses as much as digits as its factorization.

53474833 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 37.

The square root of 53474833 is about 7312.6488360922. The cubic root of 53474833 is about 376.7470082971.

The spelling of 53474833 in words is "fifty-three million, four hundred seventy-four thousand, eight hundred thirty-three".