Base | Representation |
---|---|
bin | 100110111011010010110… |
… | …0101000100100100011011 |
3 | 200221110022112220021221002 |
4 | 1031312211211010210123 |
5 | 1200123311113222303 |
6 | 15213432305335215 |
7 | 1061345201506016 |
oct | 115664545044433 |
9 | 20843275807832 |
10 | 5350012242203 |
11 | 1782a22488632 |
12 | 724a5033750b |
13 | 2ca67235aba5 |
14 | 146d28ac437d |
15 | 94275892788 |
hex | 4dda594491b |
5350012242203 has 2 divisors, whose sum is σ = 5350012242204. Its totient is φ = 5350012242202.
The previous prime is 5350012242181. The next prime is 5350012242221. The reversal of 5350012242203 is 3022422100535.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5350012242203 - 212 = 5350012238107 is a prime.
It is not a weakly prime, because it can be changed into another prime (5350012212203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2675006121101 + 2675006121102.
It is an arithmetic number, because the mean of its divisors is an integer number (2675006121102).
Almost surely, 25350012242203 is an apocalyptic number.
5350012242203 is a deficient number, since it is larger than the sum of its proper divisors (1).
5350012242203 is an equidigital number, since it uses as much as digits as its factorization.
5350012242203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 5350012242203 its reverse (3022422100535), we get a palindrome (8372434342738).
The spelling of 5350012242203 in words is "five trillion, three hundred fifty billion, twelve million, two hundred forty-two thousand, two hundred three".
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