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5352146131 is a prime number
BaseRepresentation
bin1001111110000001…
…10100010011010011
3111211000000012020111
410333000310103103
541430122134011
62243031022151
7246426330403
oct47700642323
914730005214
105352146131
1122a7168672
12105450a957
13673ab6897
1438ab6a803
15214d16121
hex13f0344d3

5352146131 has 2 divisors, whose sum is σ = 5352146132. Its totient is φ = 5352146130.

The previous prime is 5352146123. The next prime is 5352146167. The reversal of 5352146131 is 1316412535.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5352146131 - 23 = 5352146123 is a prime.

It is a super-2 number, since 2×53521461312 = 57290936415156538322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5352146093 and 5352146102.

It is not a weakly prime, because it can be changed into another prime (5352146101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676073065 + 2676073066.

It is an arithmetic number, because the mean of its divisors is an integer number (2676073066).

Almost surely, 25352146131 is an apocalyptic number.

5352146131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5352146131 is an equidigital number, since it uses as much as digits as its factorization.

5352146131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10800, while the sum is 31.

The square root of 5352146131 is about 73158.3633701575. The cubic root of 5352146131 is about 1749.2128303018.

Adding to 5352146131 its reverse (1316412535), we get a palindrome (6668558666).

The spelling of 5352146131 in words is "five billion, three hundred fifty-two million, one hundred forty-six thousand, one hundred thirty-one".