Base | Representation |
---|---|
bin | 11000010101101101000110… |
… | …11111110100101101000001 |
3 | 21000111200111020102101120020 |
4 | 30022312203133310231001 |
5 | 24003402213102112001 |
6 | 305455452540204053 |
7 | 14162601146621022 |
oct | 1412664337645501 |
9 | 230450436371506 |
10 | 53522330504001 |
11 | 16065769277447 |
12 | 6004ba0239629 |
13 | 23b3198840c08 |
14 | d306cd338c49 |
15 | 62c38a64c736 |
hex | 30ada37f4b41 |
53522330504001 has 4 divisors (see below), whose sum is σ = 71363107338672. Its totient is φ = 35681553669332.
The previous prime is 53522330503921. The next prime is 53522330504003. The reversal of 53522330504001 is 10040503322535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53522330504001 - 235 = 53487970765633 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53522330504003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8920388417331 + ... + 8920388417336.
It is an arithmetic number, because the mean of its divisors is an integer number (17840776834668).
Almost surely, 253522330504001 is an apocalyptic number.
It is an amenable number.
53522330504001 is a deficient number, since it is larger than the sum of its proper divisors (17840776834671).
53522330504001 is a wasteful number, since it uses less digits than its factorization.
53522330504001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17840776834670.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 53522330504001 its reverse (10040503322535), we get a palindrome (63562833826536).
The spelling of 53522330504001 in words is "fifty-three trillion, five hundred twenty-two billion, three hundred thirty million, five hundred four thousand, one".
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