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53534012002 = 226767006001
BaseRepresentation
bin110001110110111000…
…000011001001100010
312010011212200120201021
4301312320003021202
51334114201341002
640332043400054
73603423410512
oct616670031142
9163155616637
1053534012002
1120781610629
12a46052302a
135081c874a3
14283bc23842
1515d4c6e737
hexc76e03262

53534012002 has 4 divisors (see below), whose sum is σ = 80301018006. Its totient is φ = 26767006000.

The previous prime is 53534011897. The next prime is 53534012009. The reversal of 53534012002 is 20021043535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 42193678921 + 11340333081 = 205411^2 + 106491^2 .

It is not an unprimeable number, because it can be changed into a prime (53534012009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13383502999 + ... + 13383503002.

Almost surely, 253534012002 is an apocalyptic number.

53534012002 is a deficient number, since it is larger than the sum of its proper divisors (26767006004).

53534012002 is a wasteful number, since it uses less digits than its factorization.

53534012002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26767006003.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 53534012002 its reverse (20021043535), we get a palindrome (73555055537).

The spelling of 53534012002 in words is "fifty-three billion, five hundred thirty-four million, twelve thousand, two".

Divisors: 1 2 26767006001 53534012002