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53534422537 is a prime number
BaseRepresentation
bin110001110110111001…
…100111011000001001
312010011220110102212021
4301312321213120021
51334114303010122
640332100244441
73603430040431
oct616671473011
9163156412767
1053534422537
1120781871012
12a4606a0721
13508209c2cb
14283bccd2c1
1515d4d011c7
hexc76e67609

53534422537 has 2 divisors, whose sum is σ = 53534422538. Its totient is φ = 53534422536.

The previous prime is 53534422481. The next prime is 53534422561. The reversal of 53534422537 is 73522443535.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36060490816 + 17473931721 = 189896^2 + 132189^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53534422537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53534422493 and 53534422502.

It is not a weakly prime, because it can be changed into another prime (53534422597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26767211268 + 26767211269.

It is an arithmetic number, because the mean of its divisors is an integer number (26767211269).

Almost surely, 253534422537 is an apocalyptic number.

It is an amenable number.

53534422537 is a deficient number, since it is larger than the sum of its proper divisors (1).

53534422537 is an equidigital number, since it uses as much as digits as its factorization.

53534422537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512000, while the sum is 43.

The spelling of 53534422537 in words is "fifty-three billion, five hundred thirty-four million, four hundred twenty-two thousand, five hundred thirty-seven".