Base | Representation |
---|---|
bin | 110001110111010000… |
… | …011101011011101010 |
3 | 12010012022201200122102 |
4 | 301313100131123222 |
5 | 1334122321123424 |
6 | 40332432453402 |
7 | 3603531662021 |
oct | 616720353352 |
9 | 163168650572 |
10 | 53540411114 |
11 | 20785191353 |
12 | a4626aa262 |
13 | 50833b8048 |
14 | 283ca0b8b8 |
15 | 15d55d57ae |
hex | c7741d6ea |
53540411114 has 4 divisors (see below), whose sum is σ = 80310616674. Its totient is φ = 26770205556.
The previous prime is 53540411107. The next prime is 53540411123. The reversal of 53540411114 is 41111404535.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 30749376025 + 22791035089 = 175355^2 + 150967^2 .
It is a super-2 number, since 2×535404111142 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13385102777 + ... + 13385102780.
Almost surely, 253540411114 is an apocalyptic number.
53540411114 is a deficient number, since it is larger than the sum of its proper divisors (26770205560).
53540411114 is a wasteful number, since it uses less digits than its factorization.
53540411114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26770205559.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 53540411114 its reverse (41111404535), we get a palindrome (94651815649).
The spelling of 53540411114 in words is "fifty-three billion, five hundred forty million, four hundred eleven thousand, one hundred fourteen".
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