Base | Representation |
---|---|
bin | 1001111110010000… |
… | …11001111001011011 |
3 | 111211010202020122011 |
4 | 10333020121321123 |
5 | 41431124311011 |
6 | 2243141410351 |
7 | 246452253262 |
oct | 47710317133 |
9 | 14733666564 |
10 | 5354135131 |
11 | 22a82a6a74 |
12 | 10551099b7 |
13 | 674331cc7 |
14 | 38b1275d9 |
15 | 2150aa621 |
hex | 13f219e5b |
5354135131 has 2 divisors, whose sum is σ = 5354135132. Its totient is φ = 5354135130.
The previous prime is 5354135081. The next prime is 5354135161. The reversal of 5354135131 is 1315314535.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5354135131 - 221 = 5352037979 is a prime.
It is a super-2 number, since 2×53541351312 = 57333526002016774322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5354135093 and 5354135102.
It is not a weakly prime, because it can be changed into another prime (5354135161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677067565 + 2677067566.
It is an arithmetic number, because the mean of its divisors is an integer number (2677067566).
Almost surely, 25354135131 is an apocalyptic number.
5354135131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5354135131 is an equidigital number, since it uses as much as digits as its factorization.
5354135131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13500, while the sum is 31.
The square root of 5354135131 is about 73171.9559052510. The cubic root of 5354135131 is about 1749.4294881519.
Adding to 5354135131 its reverse (1315314535), we get a palindrome (6669449666).
The spelling of 5354135131 in words is "five billion, three hundred fifty-four million, one hundred thirty-five thousand, one hundred thirty-one".
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