Base | Representation |
---|---|
bin | 100110111101010110000… |
… | …0001111010011011100001 |
3 | 200221212200102021120210001 |
4 | 1031322230001322123201 |
5 | 1200211320322332231 |
6 | 15215441241140001 |
7 | 1061562256145164 |
oct | 115725401723341 |
9 | 20855612246701 |
10 | 5354415433441 |
11 | 1784881a17358 |
12 | 72587aa8a601 |
13 | 2cabc466a5a9 |
14 | 1472257cdadb |
15 | 9443220bb61 |
hex | 4deac07a6e1 |
5354415433441 has 2 divisors, whose sum is σ = 5354415433442. Its totient is φ = 5354415433440.
The previous prime is 5354415433337. The next prime is 5354415433511. The reversal of 5354415433441 is 1443345144535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5295042801216 + 59372632225 = 2301096^2 + 243665^2 .
It is a cyclic number.
It is not a de Polignac number, because 5354415433441 - 29 = 5354415432929 is a prime.
It is a super-2 number, since 2×53544154334412 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5354415433391 and 5354415433400.
It is not a weakly prime, because it can be changed into another prime (5354415433141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677207716720 + 2677207716721.
It is an arithmetic number, because the mean of its divisors is an integer number (2677207716721).
Almost surely, 25354415433441 is an apocalyptic number.
It is an amenable number.
5354415433441 is a deficient number, since it is larger than the sum of its proper divisors (1).
5354415433441 is an equidigital number, since it uses as much as digits as its factorization.
5354415433441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3456000, while the sum is 46.
The spelling of 5354415433441 in words is "five trillion, three hundred fifty-four billion, four hundred fifteen million, four hundred thirty-three thousand, four hundred forty-one".
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