Base | Representation |
---|---|
bin | 11000010110100000110111… |
… | …00001100101000111001010 |
3 | 21000121100012112000221212100 |
4 | 30023100123201211013022 |
5 | 24004331113143042442 |
6 | 305520325513454230 |
7 | 14164603514003406 |
oct | 1413203341450712 |
9 | 230540175027770 |
10 | 53550114034122 |
11 | 16076526361892 |
12 | 600a454a11376 |
13 | 23b59a5958c74 |
14 | d31ba725a106 |
15 | 62ce648a484c |
hex | 30b41b8651ca |
53550114034122 has 12 divisors (see below), whose sum is σ = 116025247073970. Its totient is φ = 17850038011368.
The previous prime is 53550114034061. The next prime is 53550114034199. The reversal of 53550114034122 is 22143041105535.
53550114034122 is a `hidden beast` number, since 5 + 3 + 5 + 501 + 140 + 3 + 4 + 1 + 2 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 45911750224041 + 7638363810081 = 6775821^2 + 2763759^2 .
It is a super-2 number, since 2×535501140341222 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1487503167597 + ... + 1487503167632.
Almost surely, 253550114034122 is an apocalyptic number.
53550114034122 is an abundant number, since it is smaller than the sum of its proper divisors (62475133039848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53550114034122 is a wasteful number, since it uses less digits than its factorization.
53550114034122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2975006335237 (or 2975006335234 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 53550114034122 its reverse (22143041105535), we get a palindrome (75693155139657).
The spelling of 53550114034122 in words is "fifty-three trillion, five hundred fifty billion, one hundred fourteen million, thirty-four thousand, one hundred twenty-two".
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