Base | Representation |
---|---|
bin | 100110111101110011101… |
… | …1100010010010111111001 |
3 | 200221222020212212201120011 |
4 | 1031323213130102113321 |
5 | 1200220341010444001 |
6 | 15220124205301521 |
7 | 1061626051432660 |
oct | 115734734222771 |
9 | 20858225781504 |
10 | 5355412203001 |
11 | 1785243634053 |
12 | 725ab88648a1 |
13 | 2cb023016273 |
14 | 1472bbd39dd7 |
15 | 9448e9a0d51 |
hex | 4dee77125f9 |
5355412203001 has 8 divisors (see below), whose sum is σ = 6120585720704. Its totient is φ = 4590267343200.
The previous prime is 5355412202993. The next prime is 5355412203013. The reversal of 5355412203001 is 1003022145535.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5355412203001 - 23 = 5355412202993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5355412203091) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6762525 + ... + 7512826.
It is an arithmetic number, because the mean of its divisors is an integer number (765073215088).
Almost surely, 25355412203001 is an apocalyptic number.
It is an amenable number.
5355412203001 is a deficient number, since it is larger than the sum of its proper divisors (765173517703).
5355412203001 is a wasteful number, since it uses less digits than its factorization.
5355412203001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14328951.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 5355412203001 its reverse (1003022145535), we get a palindrome (6358434348536).
The spelling of 5355412203001 in words is "five trillion, three hundred fifty-five billion, four hundred twelve million, two hundred three thousand, one".
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